Self Evaluation

Q1. The advantages of continuous cultivation are:
A    Ease of process control
B    Significant improvement in yield and productivity
C    Its ability to study culture physiological behavior
D    All of the above

Q2. The disadvantages of Continuous cultivation are:
A    Development of mutant
B    Significant wall growth
C    Significantly high equipment and accessories cost
D    All of the above

Q3. Monod model is:
A    An Empirical model
B    An Unstructured model
C    Unable to describe the transients in Continuous cultivation
D    All of the above

Q4. The unit of productivity is:
A    g/L
B    g/L-h
C    g/g –h
D    g/g

Q5. Wash out of Continuous cultivation is a condition:
A    When Dilution rate D =µmax
B    When substrate concentration in the reactor is equal to substrate concentration in feed
C    When product concentration in the reactor is zero
D    All of the above

Q6. At D = 0.05 h-1 the Chemostat:
A    Will have low unconverted substrate
B    Will have slow growth of the culture
C    Will have very high residence time in the reactor
D    All of the above

Q7. Dilution rate of Continuous cultivation is given by (F=Feed rate, V=Reactor Volume):
A    D = F/V
B    D = FV
C    D = V/F
D    None of the above

Q8. The highest productivity of the biomass in Chemostate will be observed:
A    At lowest dilution rate
B    At highest dilution rate
C    At dilution rate different than A & B
D    None of the above

Q9. Physiological state marker in Continuous cultivation:
A    Adequately reflects the physiology of the culture
B    Is usually the intracellular concentration of the cell component
C    Can describe the culture metabolism better than Biomass concentration in the
            mathematical model
D    All of the above

Q10. For maintaining steady state of exponentially growing culture in Chemostat, the
         Medium Feed rate in the reactor will have to be kept:
A    Kept high
B    Kept low
C    Kept neither too high nor too low
D    Extremely low